Elderly holistic health management model According to the principle of threefold in Thai society

Abstract

The purposes of this research article were 1) to study the state of holistic well-being management, 2) to develop a holistic well-being management model, and 3) to propose a model of holistic well-being management of the elderly according to the threefold training in Thai society. Mixed methods research was designed. Quantitative data were collected from 500 monks and the elderly, and were analyzed by descriptive statistics consisted of percentage, mean, standard deviation including Pearson correlation analysis and model analysis with computer package programs. Qualitative data were collected by interview 10 key informants and focus group discussion with 10 experts. Results indicated that the state of holistic well-being management of the elderly in all 4 aspects was at a high level. All the variables were shown the correlation with statistically significant at the .001 level, and the correlation coefficients ranged from .664 to .839. The correlation matrix between factors was significantly different from the identity matrix. Holistic health management model was developed which consisted of 4 parts: Part 1 Introduction, Part 2 Model, Part 3 Procedure for utilization, Part 4 Conditions for success. A model for the holistic well-being management of the elderly according to the threefold training in Thai society consisted of 4 parts. Part 1: Introduction, Part 2: Prototype of holistic well-being factors on the aspect of physical, mental, social, intellectual/spiritual aspects, and the threefold training including 4 sets of knowledge of self-care and potential development of the elderly, Part 3 steps of utilization integrated with the threefold training, and Part 4: Conditions for success was validated the model with empirical data (MHHM). The results of 161 tests of the conformity of the model with found that the model was consistent with the empirical data based on the chi-square value (2 ) = 261.89, df = 132, p = 0.089.